GMD-750-R Eaton 750 mA Time-Lag Glass Fuse 250 Vac
GMD-750-R Eaton 750 mA Time-Lag Glass Fuse 250 Vac

GMD-750-R Eaton 750 mA Time-Lag Glass Fuse 250 Vac

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pEaton GMD-750-R — 750 mA, 250 V, time-delay glass cartridge fuse, 35 A at 250 Vac; 10,000 A at 125 Vac interrupting./p
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    GMD-750-R Eaton 750 mA Time-Lag Glass Fuse 250 Vac

    GMD-750-R Eaton 750 mA Time-Lag Glass Fuse 250 Vac belongs to the the maker range. It carries 750 mA, rated 250 Vac, uses a time-delay element, in a glass body.

    Technical Data

    ParameterRating
    Part numberGMD-750-R
    Elementsingle element
    AC interrupting rating35 A at 250 Vac; 10,000 A at 125 Vac
    Rated current750 mA (3/4 A)
    Typical melting I2t4.7 A²s
    Design standardUL/CSA 248-14
    End capsnickel-plated brass
    Typical DC cold resistance0.3065 Ω
    Voltage rating250 Vac
    Maximum voltage drop410 mV
    BodyGlass tube, 5 x 20 mm

    Design Notes

    • Interrupting capability is 35 A at 250 Vac; 10,000 A at 125 Vac — confirm the circuit's prospective fault current stays below this.
    • Time-delay element rides through motor starting and capacitive inrush without nuisance opening.
    • Startup surges of several times rated current are tolerated for a short window.
    • Glass body lets you inspect the element after a fault.
    • Best kept for lower fault-current circuits where visual diagnosis matters.
    • Working voltage must stay at or below 250 Vac; a lower-rated part is not a safe substitute.
    • Do not upsize beyond 750 mA to stop nuisance trips — fix the cause instead.

    Where It Is Used

    Typical places this fuse turns up:

    • EV

    Common Questions

    What are the ratings of the GMD-750-R?

    750 mA continuous at 250 Vac, interrupting rating 35 A at 250 Vac; 10,000 A at 125 Vac.

    Is the GMD-750-R fast-acting or time-delay?

    It is time-delay. It tolerates short inrush surges.

    Can the GMD-750-R be used on a higher fault-current circuit?

    No — its interrupting rating is 35 A at 250 Vac; 10,000 A at 125 Vac. Choose a part whose breaking capacity exceeds the prospective fault current.

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