Littelfuse 021802.5 218 Series 2.5 A 5×20mm Glass Tube Through-Hole Fuse
Littelfuse 021802.5 218 Series 2.5 A 5×20mm Glass Tube Through-Hole Fuse

Littelfuse 021802.5 218 Series 2.5 A 5×20mm Glass Tube Through-Hole Fuse

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pLittelfuse 021802.5 — 2.5 A, 250 V, glass cartridge fuse, 35A@250VAC interrupting./p
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    Littelfuse 021802.5 218 Series 2.5 A 5×20mm Glass Tube Through-Hole Fuse

    Built by Littelfuse, the 021802.5 carries 2.5 A, rated 250 VAC, in a glass body.

    Technical Data

    ParameterRating
    ParameterValue
    Manufacturer / SeriesLittelfuse / 218 Series
    Part number021802.5
    Fuse characteristictime-delay (T)
    Rated current2.5 A
    Voltage rating250 VAC
    Interrupting rating35A@250VAC
    Nominal cold resistance0.0219 Ω
    Nominal melting I²t23.25 A²·s
    Package / mounting5 × 20 mm glass tube (IEC 60127-2 Sheet 3)
    Operating temperature2 °C
    Agency / environmentalUL 248-14 / IEC 60127-2 compliant, RoHS compliant and lead-free

    Selection Notes

    • Interrupting capability is 35A@250VAC — confirm the circuit's prospective fault current stays below this.
    • Glass body lets you inspect the element after a fault.
    • Best kept for lower fault-current circuits where visual diagnosis matters.
    • Working voltage must stay at or below 250 VAC; a lower-rated part is not a safe substitute.
    • Do not upsize beyond 2.5 A to stop nuisance trips — fix the cause instead.

    Typical Applications

    Engineers usually specify it for these duties:

    • adapter
    • industrial control
    • lighting
    • appliance
    • surge
    • transformer

    Part Number and Packing

    Order code 021802.5 from Littelfuse, supplied in 5 × 20 mm glass tube (IEC 60127-2 Sheet 3). Confirm the exact suffix before release.

    Q&A

    What are the ratings of the 021802.5?

    2.5 A continuous at 250 VAC, interrupting rating 35A@250VAC.

    Can the 021802.5 be used on a higher fault-current circuit?

    No — its interrupting rating is 35A@250VAC. Choose a part whose breaking capacity exceeds the prospective fault current.

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