Littelfuse 04643.15DR 3.15 A 464 fast-acting SMD Fuse
Littelfuse 04643.15DR 3.15 A 464 fast-acting SMD Fuse

Littelfuse 04643.15DR 3.15 A 464 fast-acting SMD Fuse

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pLittelfuse 04643.15DR — 3.15 A, 250 V, fast-acting SMD fuse, 100 A @ 250 VAC interrupting./p
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    Littelfuse 04643.15DR 3.15 A 464 fast-acting SMD Fuse

    Built by Littelfuse, the 04643.15DR carries 3.15 A, rated 250 VAC, uses a fast-acting element.

    Technical Data

    ParameterRating
    ParameterValue
    Manufacturer / SeriesLittelfuse / 464 Series
    Part number04643.15DR
    Fuse characteristicfast-acting
    Rated current3.15 A
    Voltage rating250 VAC
    Interrupting rating100 A @ 250 VAC
    Nominal cold resistance0.0206 Ω
    Nominal melting I²t8.05 A²s
    Package12.1 × 4.5 mm NANO2 UMF
    Operating temperature-55 °C to +125 °C
    Agency / environmentalIEC 60127-4 UMF, PSE/UL approvals by rating, RoHS compliant and halogen-free

    Selection Notes

    • Interrupting capability is 100 A @ 250 VAC — confirm the circuit's prospective fault current stays below this.
    • Fast element suits resistive and semiconductor loads rather than motors with high inrush.
    • Because it opens within milliseconds, downstream semiconductors see less let-through energy.
    • Working voltage must stay at or below 250 VAC; a lower-rated part is not a safe substitute.
    • Do not upsize beyond 3.15 A to stop nuisance trips — fix the cause instead.

    Typical Applications

    Engineers usually specify it for these duties:

    • EV
    • lighting

    Part Number and Packing

    Order code 04643.15DR from Littelfuse, supplied in 12.1 × 4.5 mm NANO2 UMF. Confirm the exact suffix before release.

    Q&A

    What are the ratings of the 04643.15DR?

    3.15 A continuous at 250 VAC, interrupting rating 100 A @ 250 VAC.

    Is the 04643.15DR fast-acting or time-delay?

    It is fast-acting. Expect it to open quickly on overload.

    Can the 04643.15DR be used on a higher fault-current circuit?

    No — its interrupting rating is 100 A @ 250 VAC. Choose a part whose breaking capacity exceeds the prospective fault current.

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